I have to do an English report. My group is doing the topic 'Superstition in Ancient Greece'. For our visual part we're making a PowerPoint, and of course the song 'Superstition' was the first thing we thought of. I was wondering if there more modern, rock version of the song?
2007-11-09 10:27:33 · 10 answers · asked by CCSaar 1 in Entertainment & Music ➔ Music ➔ Other - Music
OK, OK! I KNOW the origional is the best version! But I got outvoted and I was told that the only way we would use 'Superstition' is if I got a "better" version.
2007-11-09 10:32:59 · update #1
The best rock version is the blues-drenched, straight-ahead power shot from Stevie Ray Vaughan.
But whoever voted down the original Stevland Morris version is one square cat. Stevie Wonder's music is international and cool.
2007-11-09 10:38:24 · answer #1 · answered by Your Uncle Dodge! 7 · 0⤊ 0⤋
Stevie Ray Vaughn's version rocks, and, in my humble opinion, is the best.
2007-11-09 10:32:26 · answer #2 · answered by Anonymous · 1⤊ 0⤋
I'm not trying to be cute, but the original is soooooo good! Use that, not some crappy knockoff.
2007-11-09 10:30:55 · answer #3 · answered by Snugs 3 · 0⤊ 1⤋
why would you defile a classic which a rock version. use the original
2007-11-09 10:30:00 · answer #4 · answered by Sexy house music 5 · 1⤊ 1⤋
red hot chilli peppers did higher ground if that is what your thinking
2007-11-09 10:31:53 · answer #5 · answered by Melted Snowman 5 · 0⤊ 0⤋
red hot chili peppers do an awesome version
your right...still great anyways
2007-11-09 10:30:02 · answer #6 · answered by Anonymous · 0⤊ 1⤋
well i think there is a remake by alicica keys...could be wrong but ckeck it out anyway
2007-11-09 10:29:49 · answer #7 · answered by Anonymous · 0⤊ 0⤋
dude. the original is by far the best.
dont replace it.
2007-11-09 10:31:01 · answer #8 · answered by puurplemooose 6 · 0⤊ 0⤋
STEVIE RAY VAUGHN
2007-11-09 10:31:00 · answer #9 · answered by HarleyD 3 · 1⤊ 1⤋
i think raven symone (idk spelling) sings it.....
2007-11-09 10:29:40 · answer #10 · answered by lexi 2 · 0⤊ 0⤋