√25x+√16x-√4x?

Answer 1

√25x+√16x-√4x

Take the first part: √25x
It can be broken up into: √25 times x, and the square root of 25 is 5, so you get 5√x.

Second part: √16x
It can be broken up into √16 times x, and the square root of 16 is 4, so you get 4√x.

Third part: √4x
It can be broken up into 4 times x, and the square root of 4 is 2, so you get 2√x.

Put it all together: 5√x + 4√x - 2√x.
Since they are all times √x, you can combine the 5, 4, and 2.

5√x + 4√x = 9√x
9√x - 2√x = 7√x

Answer: 7√x

Answer 2

√25x+√16x-√4x = 5√x+4√x-2√x = 7√x

Answer 3

If the question is √(25x) + √(16x) - √(4x) indicating that the x is also underneath the radical then you would have:

5√x + 4√x - 2√x which equals 7√x

If the equation is √25 * x + √16 * x - √4 * x ((which I doubt)) than your answer would be:

5x + 4x - 2x = 7x

Answer 4

a^2 - b^2 ≡ (a + b)(a - b) 4x^3 + 16x^2 - 25x - 100 = 0 (4x^3 + 16x^2) - (25x + 100) = 0 4x^2(x + 4) - 25(x + 4) = 0 (x + 4)(4x^2 - 25) = 0 (x + 4)[(2x)^2 - 5^2] = 0 (x + 4)(2x + 5)(2x - 5) = 0 x + 4 = 0 x = -4 2x + 5 = 0 2x = -5 x = -5/2 (-2.5) 2x - 5 = 0 2x = 5 x = 5/2 (2.5) ∴ x = -4, ±5/2 (±2.5)

Answer 5

√25x+√16x-√4x <-- I assume x is under the radical. If so,
5√x+4√x-2√x = 7√x

If the x is not under the radical, answer is 7x

You should use paretheses to eliminate ambiguities.

Answer 6

7√x

Answer 7

It's 7x.
Because, the square root of 25 is five, plus the square root of 16 which is 4. So 5+4=9.
Then you subtract the square root of 4, which is two.
So you have 5x+4x-2x.
Together it equals 7x.

Answer 8

i think 7x because teh square root of 25 is 5 16 is 4 and 4 is 2 so u have
5x+4x-2x so its 7x

Answer 9

What exactly are you looking for ? The value of x ? If that's the case, then you need an 'equation'. One which has an expression on the LHS (left hand side) and the RHS (right ..), separated by a equal to (=) symbol.

Answer 10

42