I need help i need a solution to solve a equation can anyone help ??

Question

Solve...
a) ( x - 2 )( x - 7 )=0

em so how it will be in its (p+3)(p-2)

Answer 1

Well, the only way to get a product of zero is by having one of the factors to be zero.

So for your equation, it will only be true if either (x-2) or (x-7) = 0.

x - 2 = 0
x = 2

x - 7 = 0
x = 7

Therefore, there are two possible values for x, namely x = 2 or 7

Answer 2

You must take do some thinking!
x=2 gives 0 X (2-7)=0 x -5= 0

x= 7 gives the same result.

Then x=2 and x=7 are the roots of this equitation

Answer 3

^3?(x-3)^3 = a million^3 x-3 = a million x= 4 ?(x+7)^2 = (x+a million)^2 x+7 = x^2 +2x +a million 0= x^2 +2x -x +a million -7 0= x^2 +x -6 0= (x+3)(x-2) hence x= -3, x= 2 ?(3x-8)^2 = 2^2 3x -8 = 4 3x = 12 3x/3 = 12/3 x= 4 assuming equation is: a million/3(2x+a million) = 3 divide the two sides by employing a million/3, AKA MULTIPLY the two sides by employing 3: 3(a million/3(2x+a million)) = 3(3) 2x+a million = 9 2x = 8 2x/2 = 8/2 x= 4

Answer 4

set both sets of parenthesis equal to zero then solve by adding the 2 and the 7

x-2=0 add 2
x=2

x-7=0 add 7
x=7

Answer 5

x = 2 or 7, this is pretty obvious by look at it. if x = 2 then

(2-2)x(2-7) -> 0x-5 -> 0 and vice versa

Answer 6

when multiplied out it becomes a quadratic equation;
x^2 - 9x +14 = 0 and may be solved by the formula:-
minus b plus or minus the square root of b^2 minus 4ac, all divided by 2a. a is 1, b is - 9 and c is 14 and the answers, 7 and 2, are given above.

Answer 7

(x-2)(x-7)=0
then x-2=0 or x-7=0
so, x=2 or x=7
x=2 or 7

Answer 8

( x - 2 )( x - 7 )=0

The above is a true statement if either of the factors is equal to zero, so set each to zero and solve for x

x - 2 = 0
x = 2

x - 7 = 0
x = 7

Answer 9

to get 0, one of the brackets must equal zero, so
{the first Bracket}
x-2=0 (take -2 ova)
x=0+2
x=2
{The second Bracket}
x-7=0 (Take -7 ova)
x=0+7
x=7
So, x can equal two things, either x=2, or x=7

The same pricapal is applied to the second equation, factirised thing...
(p+3)(p-2)
{the first Bracket}
p+3=0 (take ova +3)
p=0-3
p=-3
{the second Bracket}
p-2=0 (take -2 ova)
p=0+2
p=2
so, p can equal two things, either p=-3, or p=2
hope tht helps!

Answer 10

(x-2)(x-7) = 0 try multiplying the brackets, you get

x^2 - 2x -7x +14 = 0

x^2 -9x = -14 say x = 2

2x2 -9x2 = -14

4 -18 = -14 that is -14 = -14 therefore x = 2