Calculate the pH of the solution...?

1 ⤊

Calculate the pH of the solution...?

produced when 25.0 mL of 2.0M HNO3 is diluted to 750mL. Show work.

2007-11-09 09:00:07 · 2 answers · asked by moonlit skies 2 in Science & Mathematics ➔ Chemistry

2 answers

25 ml * 2.0 mole/liter * 1 liter/1000 ml = 0.05 moles HNO3

(0.05 moles HNO3 / 750 ml) * 1000ml/liter = 0.0667 M

pH = -log [H+] = -log (6.667e-2) = 1.176

2007-11-09 09:07:04 · answer #1 · answered by Dave_Stark 7 · 0⤊ 0⤋

25ml * 2 moles H+/1000ml = 0.05 moles H+

total volume = 750 ml

molarity = moles/L = 0.05 moles/0.75L = 0.067 M = [H+]

pH = -log[H+] = -log(0.067) = 1.17

2007-11-09 17:05:11 · answer #2 · answered by Dr Dave P 7 · 1⤊ 0⤋