2007-11-09 08:18:19 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use the order of operations
First do the exponents
(3a^2)^3 = 27a^6
(2a)^2 = 4a^2
Now do the multiplication
27a^6 * 4a^2 = 108a^8
so your answer when simplified is 108a^8
2007-11-09 08:26:04 · answer #1 · answered by Jamanski 3 · 0⤊ 0⤋
Given:
(3a^2)^3*(2a)^2
= (3^3a^6)*(2^2a^2)
= (27a^6)*(4a^2)
= (27*4*a^8)
= 108a^8 Answer
teddy boy
2007-11-09 16:35:06 · answer #2 · answered by teddy boy 6 · 0⤊ 0⤋
(3a^2)^3*(2a)^2?
Use the following
(a^m)^n = a^(mn), hence
(3a^2)^3 = (3^3)(a^6) = 27a^6
(2a)^2 = 4a^2
now use (a^p)(a^q) = a^(p +q)
(3a^2)^3*(2a)^2 = (27a^6)(4a^2) = 108 a^8
2007-11-09 16:28:14 · answer #3 · answered by Any day 6 · 0⤊ 0⤋
=27a^6*4a^2 = 108a^8
2007-11-09 16:24:20 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋