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∫ x * e^(px) dx

2007-11-09 06:18:46 · 2 answers · asked by cornz000 1 in Science & Mathematics Mathematics

2 answers

= e^(px) * (px-1)/p^2 + Constant

2007-11-09 06:23:38 · answer #1 · answered by Jan-Michael 2 · 0 0

use partial integration

∫ x * e^(px) dx = 1/p∫ x d e^(px) = 1/p * xe^(px) - 1/p* ∫ e^(px) dx

the last integral : ∫ e^(px) dx = 1/p * e^(px) + Constant

so netto you have

1/p * xe^(px) - 1/p^2 * e^(px) + Contant2

2007-11-09 14:24:29 · answer #2 · answered by gjmb1960 7 · 0 0

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