A handheld shopping basket 62.0cm long has a 1.81kg carton of milk at one end and a 0.722kg box of cereal at..

Question

the other end. Where should a 1.80kg container of orange juice be placed so that the basket balances at the center?

Please help me!

I really need help with this one. I need to turn in my hw.

Answer 1

OK, I'll help you work this, but if you haven't learned from the help I and others have given you on other questions, you need to explain where the hangup is. Email me if you like.

The pivot is on the centerline
CCW torque = CW torque for equilibrium

Let the milk be at the left end. Obviously the OJ needs to be to the right of center someplace, helping the cereal come up with enough CW torque to balance the CCW torque from the milk.

1.81 kg*31 cm = 1.80 kg*d + 0.722 kg* 31 cm

Solve for d.