one end. a)where should a parent push vertically downward with a force of 210N in order to hold the teeter totter level? b) where should the parent push with a force of 310N? c) How would you answer to parts a and b if the mass of the teeter totter was doubled.
2007-11-09 05:01:47 · 1 answers · asked by luawaikuuipo 1 in Science & Mathematics ➔ Physics
Please help me, I don't understand the examples in the book and I need to turn in my hw
2007-11-09 05:43:57 · update #1
Thank you so much!
2007-11-09 05:56:41 · update #2
If the system is in equilibrium,
CCW torque = CW torque.
The child's weight is
W = m*g = 18 kg*9.8 m/s^2 = 176.4 N.
Let's say the child is on the left end creating a
CCW torque of 176.4 N*2.6 m.
a) CCW torque = CW torque
176.4 N*2.6 m = 210 N*d
Solve for d. That's the distance from the pivot to the right to the point where the push should be applied .
b) Repeat with 310 N instead of 210 N.
c) The mass of the teeter totter does not enter in. This assumes the pivot is in the center, like normal tetter totters.
2007-11-09 05:47:45 · answer #1 · answered by sojsail 7 · 2⤊ 0⤋