can you calculate lim ( ( x - sin x )/x^3 ) when x-> 3 without using McLauren series or hopital rule ?
2007-11-09 04:52:19 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i'm really sorry , i meant x ->0
2007-11-09 05:01:50 · update #1
yes: for x = 0
look at the graph, or points
x=-0.5 > 0.16459
x=-0.1 > -0.166
x=-0.01 > .16666
x=0.01 > .16666
x = 0.1 0.166
x=0.5 > 0.16459
What is close to 0.166666, the answer is 1/6
2007-11-09 04:56:49 · answer #1 · answered by Mαtt 6 · 0⤊ 0⤋
[3 - sin(3)] / 3^3 =
[3 - sin(3)] / 27
since this function is continuous at 3.
2007-11-09 05:00:16 · answer #2 · answered by mr green 4 · 0⤊ 0⤋
x is in radians
(3-sin 3)/3^3 = .1058844441
2007-11-09 04:59:56 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
The meaning of "when x->3" is not clear and could make it harder to answer your question...
2007-11-09 04:58:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋