The four sides of a rhombus measures as follows.
138; 180; 155; 197; All in feet--- Can any one work out the area and help me.
2007-11-09 03:55:26 · 3 answers · asked by sunsuk42 1 in Science & Mathematics ➔ Mathematics
Even disregarding the fact that the shape cannot be a rhombus but an irregular quadrilateral as others have noticed, the area cannot be uniquely determined. You need some other information, such as the lengths of the diagonals or the measure of opposite angles of the figure.
Note too that the minimum area is zero, since 138+197 = 180+155 = 335.
The maximum area of such a quadrilateral is
√(138*180*155*197) ≈ 27540.686 ft^2
which will occur when opposite angles add to 180º
Formulas for the area of a quadrilateral are described in:
http://mathworld.wolfram.com/Quadrilateral.html
equations (3) through (9)
2007-11-09 04:18:14 · answer #1 · answered by Scott R 6 · 2⤊ 0⤋
Your quadrilateral is not a rhombus. A rhombus
must have all 4 sides congruent.
It's not even a parallelogram!
2007-11-09 12:08:19 · answer #2 · answered by steiner1745 7 · 0⤊ 1⤋
In Rhombus all the sides are equal. You have given all the sides different. It can not be rhombus. It is quadrilateral
2007-11-09 12:08:17 · answer #3 · answered by mohanrao d 7 · 1⤊ 1⤋