Find the sum of the infinite geometric series4+3+9/4+:...?

Question

a. 16/7
b. 16
c. -12
d. does not exist

Answer 1

here first term a = 4 and

common ratio r = 3/4

sum of the infinite series is given by

S(infinite) = a/(1-r) (when r<1)

S(infinite) = 4/(1-3/4) = 4/(1/4) = 4*4 = 16

Answer 2

r= 3/4
Sum = 4/(1-3/4)=16