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Can anyone help me with this problem? Solve the system by addition.
4x – 6y = –1
8x + 3y = 3

2007-11-09 02:57:05 · 5 answers · asked by smiles4u 3 in Science & Mathematics Mathematics

5 answers

4x – 6y = –1 <-- Eq 1
8x + 3y = 3 <-- Eq 2
16x +6y = 6 <-- Eq 3 = 2 times Eq 2
20x = 5 <-- Eq3 + Eq 1
x = 1/4
4(1/4) -6y = -1
-6y = -2
y = 2/3

2007-11-09 03:03:30 · answer #1 · answered by ironduke8159 7 · 0 0

First you will need to adjust your second equation so something will drop out, so multiply it by 2 to get the y coefficient to 6 the way it is in the first equation
2*(8x+3y)=2*3, 16x+6y=6, and then add that equation to the first one;
(4x-6y)+(16x+6y)=-1+6, simplifying to
20x=5, divide each side by 20 to get
x=5/20=1/4=0.25
Substitute 1/4 for x back into the first equation to get y;
4*1/4-6y=-1
1-6y=-1
-6y=-2
y=(-2)/(-6)=1/3
x=1/4 and y=1/3

2007-11-09 03:05:01 · answer #2 · answered by Mic K 4 · 0 0

this one's easy (and i think it's more helpful to tell you how to do it then to just do it for you )
you would add the Xs to the Xs and the Ys to the Ys and the numbers to the numbers and you should have your answer sooo...

(4x + 8x) + (3y + -6y) = (3 + -1)
____________________________

now since 8x+3y=3, we know that 3y=3-8x. so you can replace an occurence of 3y with (3-8x) and continue solving for x.

(4x + 8x) + ((3-8x) - 2(3- 8x)) = 2

2007-11-09 04:38:21 · answer #3 · answered by Nicole M 1 · 0 0

8x-12y = -2
8x+ 3y = 3
then..
-9y = 1
y= -1/9

8x + 3(-1/9) = 3
8x -1/3 = 3
8x = 9/3 + 1/3
8x = 10/3
x =10/24 = 5/12

2007-11-09 03:05:40 · answer #4 · answered by dian ps 1 · 0 0

though i dont have time to do a comprehensive explanation, but i will tell you that the only person that is right (having the right answer) is mic k above others i believe know next to nothing in maths. But it is good that they have tried. nothing is bad in trying.
x=1/4,y=1/3. even u use substitution, matrix, elimination methods you will arive at the same answer. to check, just pluck in 1/4 for x, 1/3 for y in the original equation, u will see that these are very very very very very correct. pls give mic k the BEST ANSWER. CHEERS

2007-11-09 03:21:59 · answer #5 · answered by if not jehovah 2 · 0 0

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