If one star has a temperature of 6200 K and another star has a temperature of 7800 K, how much more energy per second will the hotter star radiate from each square meter of its surface?
_______ times
How can I figure this?
2007-11-09 02:30:57 · 2 answers · asked by sweetnovember4 2 in Science & Mathematics ➔ Astronomy & Space
The power of radiation is related to the frequency of the radiation.
The frequency of the radiation is directly proportional to the power of radiation as a function of temperature.
So the percent power of radiation of the smaller star to the Biger star is equal to the ratio of 6200 /7600.
In other words the bigger star radiates 1.225 times more Power than the smaller star.
2007-11-09 03:02:56 · answer #1 · answered by goring 6 · 0⤊ 0⤋
you don't have how large the surface of the star is? It would be impossible to calcutlate with out that.
2007-11-09 10:42:23 · answer #2 · answered by M the Magnificent 3 · 0⤊ 0⤋