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What is the lift (in newtons) due to Bernoulli's principle ona wing of area 78 m^2 if the air passes over the top and bottom surfaces at speeds of 260 m/s and 150 m/s, respectively?

2007-11-08 21:23:02 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

You need to know the air density ρ. The reference value for dry, sea-level, 0 C air is 1.292 kg/m^3 (ref. 1). Then, by Bernoulli (ref. 2), the pressures on each side of the wing are
P = ρv^2/2 + ρgh + const.
The ρgh term is usually neglected since wing thickness is negligible, and in this case not given.
Net force on the wing is F = area * (P1-P2) = area * ρ(v1^2-v2^2)/2 = 2272499 N.

2007-11-09 01:23:11 · answer #1 · answered by kirchwey 7 · 5 0

http://en.wikipedia.org/wiki/Bernoulli's_principle

2007-11-08 21:33:50 · answer #2 · answered by Anonymous · 0 9

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