f(x)= 4x^(-5) let g(x) = x^3/4 perform the indicated operation and state the domain
f(f(x))
2007-11-08 14:58:49 · 4 answers · asked by Riddle 1 in Science & Mathematics ➔ Mathematics
since it's ff(x) you didn't have to give the g(x) function ;)
ff(x)
=f(f(x)) <-- it's means you insert the f(x) into itself
=f[4x^(-5)]
=4[4x^(-5)]^(-5)
=4[(4^(-5))(x^25)]
=(4/(4^5)) x^25
=(1/(4^4)) x^25
=(x^25)/(256)
2007-11-08 15:04:02 · answer #1 · answered by ٩(●̮̮̃•̃)۶ƃuılıǝɔ ǝɥʇ uo ƃuıɔuɐp 3 · 0⤊ 0⤋
(f o g)(x) is the comparable as f(g(x)) you basically placed g(x) the place the x's in f(x) are its such as you will possibly do in any equation 2x-7 rather of utilising x u use the formulation for g(x) so 2(x^2 +4)-7 2(x^2)+8-7 2(x^2)+a million
2016-09-28 21:13:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
f(f(x)) = f( 4x^(-5)) = 4[4x^(-5)]^(-5) =
4[ 4^(-5)•x^25] = x^25 / 4^4 =
x^25 / 256
2007-11-08 15:07:59 · answer #3 · answered by Philo 7 · 1⤊ 0⤋
wow ummmm is it g composite or what. please add detalis if possible. =]
2007-11-08 15:07:08 · answer #4 · answered by MJ 5 · 0⤊ 1⤋