Buoyant Force?

Question

Here's the question from the text book for my home work:
An object that weighs 340 N is floating on a lake. What is the buoyant force on it? What is the weight of the displaced water?

Is this even possible to solve, if so, can you send me the equation or something?

Thanks a ton, had a major brain fart, and once I posted I kind of figured it out, just wanted to make sure
It hit me that the weight of the object would be the buoyant force, and the weight of the water

Answer 1

Then the buoyant force = weight of the water displaced
and
If the object floats then its weight = then the buoyant force that fluid exerts on that object.

Fb=W(H20 displaced)=340N

Answer 2

well, its easy.
first, don't go by formulas ok

just think, if the body is floating, then all the forces on it must be balanced, right

so, if there is a force of 340 N acting on it from up, there is a force of same magnitude acting on it from down.

and the only force which can act from down is the buoyant force of water.

therefore buoyant force = 340 N

and remember, buoyant force = weight of water displaced

340 N = weight of water

340 N = mass of water * gravity

340 N = volume of water * density of water * gravity

340 N = volume * 1000 kg/m^3 * 10 m/s^2

volume = 340 / 10000 m^3
= 34000 ml

Answer 3

confident. advance rigidity is in keeping with Bernoulli's concept, which says in actuality that finished fluid rigidity on a physique is the sum of static and of dynamic rigidity. The advance equation for airfoils (e.g., airplane wings) is L = a million/2 rho Cl A v^2; the place rho is atmospheric density, Cl is the coefficient of advance, A is the wing section, and v is the value of the air passing over the wing. the internet weight w = ma = W - L on the physique m having weight W = mg. while W = L, w = 0 so as that a = 0 and the physique is flying at a persevering with value of climb or descent, or is flying point. it particularly is, it particularly is no longer accelerating in the vertical path. Buoyancy is in keeping with Newton's III regulation, which says while forces are balanced the sum of forces on a physique would be 0. Buoyancy is B = Rho g V; the place Rho is the density of a liquid, g is g, and V is the quantity of liquid displaced by ability of an immersed physique having weight W = mg. m is the mass of the physique. subsequently the internet weight while immersed is w = ma = W - B; so while B = W, w = 0 and the physique will flow as its acceleration a = 0. And, as quickly as returned, the physique isn't accelerating in the vertical path. As you will discover, the two forces at the instant are not an analogous, yet there are some similarities. the two L and B cut back the internet weight w of the item the advance and buoyancy are engaged on. it particularly is, the two L and B be sure if the physique m is accelerating in the vertical path. the two L and B might nicely be utilized to any fluids... the two beverages and gases. as an occasion, atomic subs actually "fly" while submersed in the oceans. They use Bernoulli's concept to circulate. And balloons, use buoyancy to drift in air.