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Not the rotation speed but the forward motion of it's orbit.

2007-11-08 13:57:12 · 8 answers · asked by Anonymous in Science & Mathematics Astronomy & Space

8 answers

19 miles a second. 68,400 MPH. Or about 1.6 million miles a day.

2007-11-08 14:00:05 · answer #1 · answered by Brant 7 · 0 0

Since Earth's orbit around the sun is elliptical and not perfectly circular, its speed varies slightly depending on where it's located in that orbit. The *mean* velocity of Earth around the sun is 30 km/sec, or 67,108 mph

Here are some other speeds you might find interesting --

Our solar system orbits the center of the Milky Way galaxy at about 250 km/sec, or 560,000 mph

Relative to the cosmic microwave background radiation, the sun is moving in the general direction of the Cup constellation at about 1.3 km/hr, or 80,7782 mph

Our solar system is moving slowly towards the center of the Milky Way galaxy at 10 ^ minus 10 meters/second

The Milky Way galaxy rotates at about 220 km/sec, or 450,000 mph

The local cluster of galaxies that the Milky Way belongs to is moving towards a distant super cluster of galaxies at 600 km/sec, or 1.3-million mph

2007-11-08 15:34:16 · answer #2 · answered by Chug-a-Lug 7 · 0 0

The circumference of the Earth at the equator is 25,000 miles. The Earth rotates in about 24 hours. Therefore, if you were to hang above the surface of the Earth at the equator without moving, you would see 25,000 miles pass by in 24 hours, at a speed of 25000/24 or just over 1000 miles per hour.

Multiply by cosine of your latitude to see how fast the Earth is rotating where you are.

Earth is also moving around the Sun at about 67,000 miles per hour.

2007-11-08 14:05:30 · answer #3 · answered by Anonymous · 0 0

19 Miles / Second

You can calculate this yourself if you wish...
While the Earth's orbit is not a circle, on average, its distance from the Sun is 93,000,000 Miles. Assuming for the sake of argument that it was a circle, that distance would be "R" in
geometry or the Radius, and the circumference of the orbital path would be 2PiR in length...so multiply 2Pi X 93,000,000.

Then divide that by 365 1/4 Days = Miles per day speed.

then divide that by 24 = Miles per hour speed

then divide that by 60 = Miles per minute speed

and finally divide that by 60 again = Miles per second speed

2007-11-08 15:00:21 · answer #4 · answered by zahbudar 6 · 0 0

29.783 km/s
107,218 km/h

all you have to do is calculate the speed from the distance from the earth to the moon find the circumference of the orbit and divide that by the time (one year). then convert to your required measurement

2007-11-08 14:01:43 · answer #5 · answered by Very confused 4 · 0 0

Are you mad? the sun, (and the rest of the universe), orbits the earth. Everyone knows that!

2007-11-08 14:07:02 · answer #6 · answered by Anonymous · 0 1

60 miles per second.

EDIT: Oops...KBW's right. I miscalculated.

Here's an explanation:

http://curious.astro.cornell.edu/question.php?number=356

2007-11-08 14:00:23 · answer #7 · answered by JMH 4 · 0 0

I would like to buy a vowel.

2007-11-08 14:00:26 · answer #8 · answered by Freeway Ricky Ross 2 · 0 1

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