a wild type fly is heterozygous for gray body color and normal wings is mated with a black fly that has vestigial wings. The offspring have the foloying phenotypic distribution:
wildtype: 778
black body vesitgial wings 785
black body, normal wings-158
gray body, vestigial wings-162
In another cross a wild type fly is heterozygous for gray body color and red eyes is mated wtih a black fly with purple eyes. the offspring are as follows:
wildtype: 721
black body, purple eyes: 751
gray body, purple eyes 49
black body, red eyes 45
Q: what fruit flies(genotypes and phenotypes) would you mate to determine the sequence of body color, wingsize and eye color geones on the chromose.
I have the answer has purple vestigial x hetero for p and v, but i'm not sure iff that is correct. please explain how you get the answer
2007-11-08 13:30:50 · 1 answers · asked by Ashley P 1 in Science & Mathematics ➔ Zoology
Cross triple heterozygotes with a tester stock that is homozygous recessive for all traits to determine order.
(normal wing, gray body, red eyes) x (vest. wing, black body, purple eyes)
v'v'b'b'p'p' x vvbbpp => v'vb'bp'p
Backcross
v'vb'bp'p x vvbbpp =>
v'vb'bp'p, v'vb'bpp, v'vbbp'p, v'vbbpp, vvbbpp, vvb'bpp, vvbbp'p, vvv'bp'p
8 phenotypes
Parental types are more numerous than recombinant.
Crossover frequency is found by adding the new types and dividing by the total number of offspring.
vpb is the correct order
2007-11-08 20:29:42 · answer #1 · answered by gardengallivant 7 · 1⤊ 0⤋