Solving Quadratics
x(squared)+5x=0
2007-11-08 12:18:19 · 5 answers · asked by Rosey 2 in Science & Mathematics ➔ Mathematics
x(x+5)=0
Then you just set x=0 and x+5=0 and solve for x in both; in this case, x = 0, -5.
2007-11-08 12:25:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x^2 + 5x = 0
x(x + 5) = 0
x = 0 or x = -5
2007-11-08 20:27:27 · answer #2 · answered by Franklin Delano Bluth 4 · 0⤊ 0⤋
you can put it into the quadradic equation so its:
x^2+5x=0
a=1, b=5, c=0
x= (-5 (+-)(square root)(5^2-4(1)(0)))/2(1)
x=(-5+5)/2, (-5-5)/2
x=0,-5
or
factor x out so its: x(x+5)=0
x=0, x+5=0
x=0, -5
2007-11-08 20:29:20 · answer #3 · answered by aod43254 3 · 0⤊ 0⤋
x^2+5x=0
x(x+5)=0
x=0 x=-5
2007-11-08 20:25:32 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
6xsquared = 0
0=0
I think this is right.
2007-11-08 20:24:21 · answer #5 · answered by C-DOG 3 · 0⤊ 0⤋