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4 answers

a² + b² = h²
a² + b² + h² = 200
h² + h² = 200
2h² = 200
h² = 100
h = 10

The hypotenuse is 10 units.

2007-11-08 12:19:42 · answer #1 · answered by gudspeling 7 · 0 0

If the sides are a, b, and c, with c the hypotenuse, then we have a² + b² = c². In addition, we're told that a² + b² + c² = 200. So

200 = (a² + b²) + c² = c² + c² = 2c²

So c²=100 and so c=10

2007-11-08 12:22:29 · answer #2 · answered by Ron W 7 · 0 0

you know that for a right triangle that a^2 + b^2 = c^2

Your problem says that a^2 + b^2 + c^2 = 200
substitute c^2 in for the a^2 + b^2 because of pythag. theorem

c^2 + c^2 = 200
2c^2 = 200
c^2 = 100
c = 10

2007-11-08 12:20:37 · answer #3 · answered by Linda K 5 · 0 0

a^2 + b^2 = c^2
a^2 + b^2 + c^2 = 200
c^2 + c^2 = 200
2c^2 = 200
c^2 = 100
c = 10

2007-11-08 12:26:56 · answer #4 · answered by ferdie 2 · 0 0

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