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This is for Calculus AB or BC students only.
Please give the steps too.

2007-11-08 11:51:30 · 4 answers · asked by singer4jc108 2 in Science & Mathematics Mathematics

4 answers

I can't tell you exactly, but don't forget the chain rule.

2007-11-08 11:58:37 · answer #1 · answered by bob jay 2 · 0 2

y´= 1/x*(2*ln x +1)

2007-11-08 19:58:55 · answer #2 · answered by santmann2002 7 · 0 0

d/dx [ln x] = 1/x
d/dx[ln² x] = 2ln(x)/x

= (2ln(x) + 1) / x

2007-11-08 19:58:31 · answer #3 · answered by Mαtt 6 · 0 0

1/2x*(2)+1/x*(1)=2/x

2007-11-08 19:58:30 · answer #4 · answered by programhelp 2 · 0 2

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