Im STUCK!!!?

Question

If a quadratic formula x^2+bx+c has exactly 1 solution (r), then find b/c....i will be picking best answer... :)

Answer 1

Dan A is correct; b/c doesn't have a fixed ratio, but b^2/c does. However, you can express the ratio b/c in terms of the solution r, which may be what you want.

Perhaps the easiest way to see this is that the quadratic will have a unique solution r if and only if
x^2 + bx + c = (x-r)^2
so b = -2r and c = r^2.

So b/c = -2/r in terms of r; and b^2/c = 4.

Answer 2

X^2+bx+c=0


u need to know that..
X= (- b)/2a



then..
plug in any coefisien..
X= -b/2
(this is the only solution)


move the -b/2 to the left
(x+b/2)^2=0



calculate that
X^2+ bX+(b^2)/4=0

then..

X^2+bx+ (b^2)/4= X^2 + bx + c

in this function...
we can determine that c= (b^2)/4

c/b= b/4


cross multiple
b/c =4/b
u get b/c...
however, the 4/b still there...


then/...


then...




then....





then I am stuck

LOL

Answer 3

Although I've never heard of a quadratic having one solution,
if you mean two solutions that are equal then

+/-2

think product sum; b=sum, c=product, when a solution to a quadratic is a pair of the same solutions, it falls that the product of them is one half the sum of them

ex

(x-1)(x-1)

x^2-2x+1

(x+1)(x+1)

x^2+4x+2

Answer 4

The quadratic discriminant is D = b^2 - 4ac. For there to be one solution, the discriminant must be equal to zero.

b^2 - 4ac = 0
b^2 - 4c = 0 (since a=1)
b/4 = c/b
b/c = 4/b

And by solution i am assuming you mean zero? What you posted isnt an equation, its an expression.