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The prime factorization of K^2 must consist of multiples of three identical prime factors.
For example:
(125)(125) = (5x5x5)(5x5x5) has six factors of five and will have an integer cube root, namely 25 [<==answer]
The next smaller integer, 4:
(4x4x4)(4x4x4) has an integer cube root, but 4x4x4 = 64 is less that 100.

2007-11-08 13:25:36 · answer #1 · answered by jsardi56 7 · 0 0

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