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A runaway truck lane heads uphill at 21 to the horizontal. If a 1.9×104 truck goes out of control and enters the lane going 120 , how far along the ramp does it go? Neglect friction.

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2007-11-08 10:36:17 · 1 answers · asked by Need help plz!!! 1 in Science & Mathematics Physics

A runaway truck lane heads uphill at 21 degrees to the horizontal. If a 1.9×104 kg truck goes out of control and enters the lane going 120km/h , how far along the ramp does it go? Neglect friction.

2007-11-08 10:43:45 · update #1

1 answers

A runaway truck lane heads uphill at 21 degrees to the horizontal. If a 1.9×104 kg truck goes out of control and enters the lane going 120km/h , how far along the ramp does it go? Neglect friction.
Conservation of energy:
KE = mv^2/2
PE = mg*dsin(21 deg)
KE = PE
d = (mv^2/2)/(mg*sin(21 deg)) = v^2/(2g*sin(21 deg))
In other words, the mass is unneeded information.
Remember to convert km/h to m/s for v.

2007-11-08 12:33:36 · answer #1 · answered by kirchwey 7 · 0 0

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