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i know the answer is f + d over c, but how would I show work for that? A statement counts as work, but I cant think of what to write. All help is appreciated. Thank you very much.

2007-11-08 10:30:53 · 12 answers · asked by Alfonso G 1 in Science & Mathematics Mathematics

12 answers

cx-d=f
cx=f+d
x=f+d/c

2007-11-08 10:33:52 · answer #1 · answered by ctxsxoc 2 · 2 0

cx - d = f
add both sides of equation by d
cx - d +d = f +d ; d substracts out on the left hand side
cx = f +d
divide both sides by c
cx / c = (f+d)/c; c divided by c = 1
x (1) = (f+d)/c
x = (f+d)/c < === answer

2007-11-08 10:46:02 · answer #2 · answered by Shh! Be vewy, vewy quiet 6 · 0 0

cx - d = f is Given
d=d Reflexive property
cx = f+d Addition property
c = (f+d)/c Division property

2007-11-08 10:36:46 · answer #3 · answered by ironduke8159 7 · 0 0

cx - d = f
D is being subtracted.. add it to the other side

cx = f+d
C and X are being multiplied.. Divide c from both sides

X = F+D/C

2007-11-08 10:36:27 · answer #4 · answered by ksm_623 3 · 0 0

many times, if a polynomial P(x) is divided by using x-n then something is P(n). So as a consequence we could locate P(2) = 2³a+2²b+2c+d, that's 8a+4b+2c+d so the respond is C. i'm hoping this helps.

2016-11-10 20:55:40 · answer #5 · answered by ? 4 · 0 0

First, you add d to both sides, so your left with: cx = f+d
Then you divide by c, so you end up with x = (f+d)/c

2007-11-08 10:34:36 · answer #6 · answered by Anonymous · 0 0

the first step is to add d to both sides, canceling it out on the left hand side. then to isolate x on one side, divide both sides by c which cancels it on the left side. then you are left with x equals f plus d all over c.

2007-11-08 10:36:09 · answer #7 · answered by victims_of_the_dark 2 · 0 0

1. cx-d+d=f+d this makes cx=d+f

2.cx/c=(f+d)/c this makes x=(f+d)/c

2007-11-08 10:36:23 · answer #8 · answered by Anonymous · 0 0

cx-d = f
cx = f+d
x = (f+d) / c

2007-11-08 10:36:58 · answer #9 · answered by Ninja...D. 3 · 0 0

cx-d=f
cx=f+d
x=(f+d)/c

2007-11-08 10:34:43 · answer #10 · answered by ss89 2 · 0 0

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