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1. a human sperm cell receive autosomes and
a y chromosome always
2. A colorblind woman marries a normal man. Which of the following is true of their children?
a. All will be colorblind.
b. All daughters will be normal and all sons will be carriers.
c. All daughters will be colorblind and all sons will be normal.
d. All daughters will be heterozygous and all sons will be colorblind.
e. It is impossible to predict with any reasonable degree of certainty.
answer is A
3. Why would you predict that half of the human babies born will be males and half will be females?
a. Because of the segregation of the X and Y chromosomes during male meiosis.
b. Because of the segregation of the X chromosomes during female meiosis.
c. Because all eggs contain an X chromosome.
d. a and b.
e. a and c.
ANSWER IS A

2007-11-08 09:38:35 · 1 answers · asked by ,,,,,,,,,,,,,,,,,, 1 in Science & Mathematics Biology

A type of muscular dystrophy shows sex-linked recessive inheritance. Affected persons usually die by the age of 15-20. Suppose that a boy with the disease lives long enough to marry a woman heterozygous for the trait. If they have a son, what is the probability that he will have the disease?
a. 25%
b. 50%
c. 75%
d. 100%
e. 0%
ANSWER IS B
Blood typing is often used as evidence in paternity cases in court. In one case, the mother had blood type B and the child had blood type O. Which of the following blood types could the father not have?
a. A
b. B
c. AB
d. O
e. Both choices c and d are correct
ANSWER IS C

2007-11-08 09:40:54 · update #1

1 answers

1. False. Human sperms have the autosomes and either an X or a Y. Half of them have X; half have a Y.
2. Colorblind woman is XbXb. Normal man is XB Y. Their daughters will be XbXB (normal/heterozygous). Their sons will be XbY (colorblind). Answer is D.
3. You're right; answer is A.
4. Mom is heterozygous XDXd; Dad has the disease XdY.
A son could be XDY or XdY with an equal chance of either outcome. So the possibility is 50%; answer is B and you are right.
5. Mom has B and child has O, so Mom must have the alleles BO (or IBi). Child's genotype is OO (or ii), and the child must have gotten one O allele from Dad. So Dad can be A (AO or IAi), Dad can be B (BO or IBi), Dad can be O (OO or ii). Dad cannot be AB because that's the only blood type that cannot possibly have an allele for O. Answer is C.

2007-11-08 09:52:50 · answer #1 · answered by ecolink 7 · 0 0

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