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A rope is stretched between supports 15 m apart. Its tension is 35 N. If one end of the rope is tweaked, the resulting disturbance reaches the other end 0.48 s later. What is the total mass of the rope?

2007-11-08 07:37:43 · 1 answers · asked by katherine g 2 in Science & Mathematics Physics

1 answers

Taut line theory (see ref.):
v = sqrt(T/(m/L))
v^2 = T/(m/L) = LT/m
m = LT/v^2
where v = 15/0.48, L = 15, T = 35

2007-11-08 12:18:32 · answer #1 · answered by kirchwey 7 · 0 0

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