a. 0.4074
b. 0.4394
c. 2.0369
d. 0.1769
Book is not helping me at all ....Please save me from my algebra disaster!
2007-11-08 07:18:43 · 9 answers · asked by Hollywood614 2 in Science & Mathematics ➔ Mathematics
4 + 3e^5x = 27
3e^5x = 23
e^5x = 23/3 = 7.6666
Take logs
5x = 2.03688
x = 0.40738
Answer: a
2007-11-08 07:35:00 · answer #1 · answered by Joe L 5 · 0⤊ 0⤋
subtract 4 from each side
3e^5x=23
divide by 3
e^5x=23/3=7.666
take the natural log of each side
5xlne=ln7.666
5x=2.0369
divide by 5
x=0.4074
2007-11-08 07:24:45 · answer #2 · answered by gang$tahtooth 5 · 0⤊ 0⤋
Divide the two sides by making use of four to get 3(4x - 8) = 12x + 9 12x - 24 = 12x + 9 Subtracting 12x from the two sides components -24 = 9. it particularly isn't extremely, regardless of cost of x you make the main of. So the respond is that there's no answer.
2017-01-06 08:00:48 · answer #3 · answered by ? 4 · 0⤊ 0⤋
3e^5x = 23
e^5x = 23/3
5x = ln(23/3)
x = .2 ln(23/3) approx = .4074 (the answer is A
2007-11-08 07:23:25 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋
remember that ln(e^x)=x
4+3e^5x=27
3e^5x=23
e^5x=23/3
take the natural log of both sides at this point.
ln(e^5x)=ln(23/3)
5x = ln(23/3)
x=(ln(23/3))/5
x=0.4074
2007-11-08 07:26:58 · answer #5 · answered by James B 2 · 0⤊ 0⤋
Just get the e^(5x) term by itself on one side, and take the natural log of both sides. That will get the 5x by itself, and then from there it's a piece of cake. Piece of crumb cake.
2007-11-08 07:24:23 · answer #6 · answered by salzano14 2 · 0⤊ 1⤋
Laced apples!
2007-11-08 07:21:45 · answer #7 · answered by mitchskram 3 · 0⤊ 1⤋
B
2007-11-08 07:22:36 · answer #8 · answered by Phil 2 · 0⤊ 1⤋
{B}
2007-11-08 07:21:13 · answer #9 · answered by Denise 1 · 0⤊ 1⤋