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A planet orbits a star at a distance of 40 AU and has an orbital period of 80 years, what is the mass of the star ( express in solar masses)

2007-11-08 05:18:56 · 2 answers · asked by la_belle_creole_2000 1 in Science & Mathematics Physics

2 answers

One form of Kepler's 3rd is
M = R^3*(2*pi/T)^2/G, thus M is proportional to R^3/T^2
Mstar/Msun =
40^3/80^2 = 10 (exactly)

2007-11-08 06:29:17 · answer #1 · answered by kirchwey 7 · 0 0

Use Kepler's law!

2007-11-08 13:25:50 · answer #2 · answered by Anonymous · 0 0

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