In an x-y coordinate system the point P is (0,-30). The polar coordinates of the point P are...
How would I go about finding this out. Thanks.
2007-11-08 04:47:49 · 4 answers · asked by Shivers20 2 in Science & Mathematics ➔ Mathematics
Magnitude = 30
Direction = - 90°
30 /_-90° is answer.
2007-11-08 05:10:02 · answer #1 · answered by Como 7 · 1⤊ 0⤋
First graph the point. That will help to find Î.
While r = â(x^2 + y^2) and tan Î = y/x you will want to get a Î that will put you in the correct quodrant. The graph will help with that.
In your case you can eye-ball the answer.
r = 30 (The distance from the origin to P), Î = Ï/2
2007-11-08 12:56:49 · answer #2 · answered by Peter m 5 · 0⤊ 0⤋
Both "wylie coyote" and"peter m" have the correct ideas. However in this case use y = r sin(theta) rather than tan(theta) = y/x to deduce that theta is 3pi/2 or -pi/2....(30,3pi/2)
2007-11-08 13:04:09 · answer #3 · answered by ted s 7 · 0⤊ 1⤋
since sin theta =-1 and r is 30
30sin -90
2007-11-08 12:54:19 · answer #4 · answered by Wylie Coyote 6 · 0⤊ 0⤋