If CD bisects AB, then the intersection is exactly half way between A and B. If D is between A and B, then it must be half way between since it is on CD. AD = DB = AB/2 = 10
2007-11-08 02:26:18
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answer #1
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answered by Andy J 7
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ok you have a triangle with verticies A,B,C right and the length from A to B is 20 you do not need to worry about the other lengths
now you have pt D between A and B
and point D is connected to C and is a bisector of A and B this means that D is exaclty in the middle of A and B
so now think of it as a line
20-x x
A_____________D_____________B
if the area from A to B is 20 then you can let the area from D to B equal x then the length from A to D has to be twenty minus x
but there is an easier way to think about it..... if AB is 20 and D is in the middle then their has to be length of 10 between D and A, and D and B
so AD=10 and DB=10
2007-11-08 10:30:53
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answer #2
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answered by mlbabe03 2
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If point D is in between points A and B and CD bisects points A and B. it means point D is the mid point of AB.
Therefore AD= 10, BD=10
2007-11-08 10:30:22
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answer #3
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answered by waqar a 1
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If CD bisects AB. The word bisect means to cut in half.
If AB is cut in half, then AD and DB are equal
AB = DB
x = 20 - x
2x = 20
x = 10
2007-11-08 10:27:43
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answer #4
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answered by Brad K 2
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If CD bisects AB, then AD = DB = 10
2007-11-08 10:25:40
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answer #5
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answered by ironduke8159 7
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There's something unclear about "~CD bisects point A and point B". Why refer to POINT A and POINT B, instead of ~AB?
Can bisect mean "two pieces, not necessarily equal"? Because otherwise the problem is too simple.
I think that Reynwater is correct and that ~CD ⥠~AB. It makes the problem more challenging but still solvable.
2007-11-08 11:08:33
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answer #6
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answered by DWRead 7
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Draw triangle ABC -- doesn't have to be to scale
Lable sides according to given
Bisecting line from point C to AB (see definition of bisect, doesn't it form a 90 degree angle?)
Then you can fly with it.
Geometry rocks!
2007-11-08 10:26:47
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answer #7
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answered by reynwater 7
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