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can you make x the subject of the following expressions?

t = 7 - 4x

t = x + 1 / x - 1

y = x^2 - 3 (x squared)


Thanks in advance

2007-11-08 01:48:52 · 3 answers · asked by mg© - anti VT™ MG AM© Fundi4Life 6 in Science & Mathematics Mathematics

3 answers

t = 7 - 4x
4x = 7 - t
x = (7 - t)/4

t = (x +1)/(x - 1)
t(x - 1) = x + 1
tx - t = x + 1
tx - x = t +1
x(t - 1) = t + 1
x = (t + 1)/(t - 1)

y = x^2 - 3
y + 3 = x^2
x^2 = y + 3
x = (y + 3)^(1/2)

2007-11-08 01:58:24 · answer #1 · answered by lkl916 1 · 0 1

t = 7-4x
4x = 7-t
x = (7-t)/4

t =(x+1)/(x-1)
t = xx -I
t+1 = xx
xx=t+1
x = the square root of (t+1)

y = x(to the nth power)2 - 3(x squared)
x(to the nth power)2= y +3(x squared)
x(to the nth power) = (y+3(x squared))/2
x = the nth root of((y+3(x squared))/2)

Sorry it's so difficult to read (I don't know how to type mathematical terms!) And I hope I have the correct answers!

2007-11-08 02:20:09 · answer #2 · answered by Anonymous · 0 0

t = 7 - 4x
4x = 7-t
x =(7-t)/4

t = (x + 1) / (x - 1) <-- I think you meant this
tx-t = x+1
tx-x = t+1
x(t-1) = t+1
x = (t+1)/(t-1)

y = x^2 - 3 (x squared)
y+3 = x^2
+/- sqrt(y+3) = x

2007-11-08 02:00:40 · answer #3 · answered by ironduke8159 7 · 0 0

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