I need help with this problem 7x^2-14x=0?

Answer 1

7x^2-14x=0
x(7x - 14) = 0

So either x = 0, or 7x-14 = 0
7x - 14 = 0
7x = 14
x = 2

Solutions are x=0 and x=2

CHECK:
When x = 0
7(0)^2 - 14(0) = 0 - 0 = 0

When x = 2
7(2)^2 - 14(2) = 7(4) - 28 = 28 - 28 = 0

Answer 2

Given 7x^2-14x=0
Take out the common factor on the left
7x(x-2) = 0
7x = 0 => x = 0
x-2 = 0 => x = 2

Answer 3

7X^2 - 14x = 0
Taking 7x common from the LHS we get
7x (x-2) = 0
Which means either 7x =0 ie x = 0
Or (x-2)=0 te x = 2
Hence x : [ 0 , 2 ]

Answer 4

If your problem is factoring out the equation, you can use the quadratic formula to help you find x:

x =[ -b +/- sqrt (b² - 4ac)] / 2a

x ={ -14 +/- sqrt [14² - 4(7)(0)]} / 2(7)

simplify:

x = -14 +/- sqrt(14² - 0) / 14
x = (-14 +/- 14) / 14

(1st)
x1 = (-14 +14) / 14
x1 = -2

(2nd)
x2 = -(14 + 14 ) / 14
x2 = 0

x is either 0 or -2

Answer 5

7x^2-14x=0
x(7x-14)=0
x=0

7x-14=0
7x=14
x=14/7
x=2

answers x=0, x=2

Answer 6

(7x) (x - 2) = 0
x = 0 , x = 2

Answer 7

7x(x-2)=0
x=0
x=2