Find angular momentum for uniform sphere. R = 0.120m, Omega = 0.600rad/s?

Question

My process, which was incorrect, is as follows:

Isphere = 2/5(14)(0.120)^2
= 0.0806 kg*m^2


L = (I)(Omega)
= (0.0806kg*m^2)(0.600rad/s)
= 0.0484 kg*m^2/s

I even tried using Isphere is m(s/2)^2, and that was incorrect. What am I doing wrong? Thanks!

I forgot to mention that the mass is 14kg. Sorry!

I am still getting an incorrect answer for this on the system. Possibly, a glitch?

Their answer was 0.484

Answer 1

The question should be clearly stated. Take note the question is as good as the answer.

Is there any information about the axis of rotation of the sphere?

For Spheres with axis of rotation passing through its center:
Is it a uniform solid sphere? Inertia = (2/5) M R²
Is it thin hollow sphere? Inertia = (2/3) M R²

For Spheres with axis of rotation not passing through its center but at some distance d, you need to use the parallel axis theorem.

Based on your additional details, you have done correct computation.