If 120 grams of sodium carbonate react with?

Question

calcium hydroxide, how many grams of sodium hydroxide are formed?

Na2CO3 + Ca(OH) 2 -------> NaOH + CaCO3,
the answer is 90.4 grams, how do i get this?
thanks

Answer 1

You use stoichiometry to convert grams of Na2CO3 to moles of Na2CO3 using molar mass, then convert moles of Na2CO3 to moles of NaOH using the equation, then convert moles of NaOH to grams of NaOH, again using molar mass.

All this conversion may be confusing, but as long as you keep your units straight, you shouldn't have much problem with it.

But first, balance the equation:

Na2CO3 + Ca(OH)2 ------> 2 NaOH + CaCO3

Now solve:

120g Na2CO3 / 106g/mol Na2CO3 = 1.13 moles Na2CO3

1.13 moles Na2CO3 = 2.26 moles NaOH (because of 1:2 ratio in equation)

2.26 moles NaOH * 40 g/mol NaOH = 90.6 grams NaOH

Answer 2

I really doubt if this reaction occurs unless the CaCO3 is being pptd out. BTW, the reactiion should indicate TWO NaOH formed. The easiest way to do this is to compute the mole wt of sodium carbonate and sodium hydroxide, and then
gm of NaOH = 2 x120 x mole wt NaOH/mole wt Na2CO3.

Answer 3

Ur eqn is unbalanced. it should be 2NaOH.

Molecular Mass of
Na2CO3 = 106
NaOH = 40
According to the eqn, 1 mol. of Na2CO3 yields 2 mol. of NaOH (this is only a ratio)

Therefore, Mass of NaOH produced= (120/106) X 2(40) = 90.5 g

Answer 4

challenging factor. seek onto search engines like google. just that may help!