How would I calculate the minimum volume (in milliteters) of O.468 M of hydrochloric acid that would be necessary to completely dissolve 1.19 grams of aluminum hydroxide. Any ideas? Thanks for any help.
2007-11-07 17:30:10 · 3 answers · asked by Christine O 1 in Science & Mathematics ➔ Chemistry
You can't play the game without a reaction, which is: 3 HCl + Al(OH)3 -> AlCl3 + 3 H2O
So, with this in hand,
(1) divide 1.19 by the mole wt of Al(OH)3, call that M.
(2) From the equation, you need 3M moles of HCl.
(3) From the relation moles=volume x molality, solve 3M = volume x 0.468. Remember if volume is in ml, you are dealing with millimoles.
2007-11-07 17:37:11 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
Convert the grams to moles by dividing 1.19g by 78 (atomic masses of Al(OH)3 added up)
then use the formula Liters=mol/M
and convert L to mL
i'm doing this kinda thing in Chem now too ...
2007-11-08 01:39:31 · answer #2 · answered by starawley 3 · 0⤊ 0⤋
0.468/1.19 squared
2007-11-08 01:32:42 · answer #3 · answered by John Bob Bryant III 2 · 0⤊ 0⤋