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A pitcher claims he can throw a baseball with as much momentum as a 3.00 g bullet moving with a speed of 2100 m/s. A baseball has a mass of 0.145 kg. What must be its speed if the pitcher's claim is valid?
m/s

2007-11-07 16:47:43 · 3 answers · asked by Anonymous in Sports Baseball

3 answers

momentum (p) = mass x velocity (mv)

bullet == baseball
(3 g) (2100 m/s) == (145 g) (v)
v = (3 *2100) / 145
v = 43.45 m/s

Does this make sense? Qualitatively, at least -- is it plausible? Well, no one ever references pitching speed in m/s, they always use mph. The conversion factor from m/s to mph is (3600/1609) or 2.24 (match up the units to cancel out and you'll find this accurate).

mph == 43.45 * 2.24
mph == 97.3 mph pitch

That's a darn good fastball, but not beyond the realm of established human performance.

The claim is plausible.

2007-11-07 17:31:05 · answer #1 · answered by Chipmaker Authentic 7 · 1 0

Your "pitcher" might have a good arm but he does not know squat about ballistics. lol

There is no such thing as a 3gr bullet > PBA(Performance Ballistic Ammo) .177 caliber pellets(5.4gr) are the lightest "bullets" I have ever heard of.

traveling at 2100m/s >3,000fps is a very high velocity round. There are very few 4,000fps+ rounds. >His 6,800fps+ round does not exist(at least not in the "real" world)

http://www.gunsandammomag.com/ballistics/ballistic-tables/

2007-11-07 20:22:00 · answer #2 · answered by C_F_45 7 · 0 0

you should probably ask this question in physics...you would get more responses

2007-11-08 01:22:22 · answer #3 · answered by casagarber 2 · 0 0

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