How many moles of iron can be recovered from 131.5 kg Fe3O4?

Answer 1

Fe3O4 Mol.mass = (3 x 56) + (4 x 16) = 232g/mole.
Fe = 56g/mole.
56/232 = 0.24 = 24% of 131.5kg
= 0.24 x 131.5 = 31.56kg Fe.
31.56kg/56kg/mole = 6.312moles Fe.

Answer 2

molar mass of Fe3O4 =3*56+4*16=232 from which the iron ha a fraction 168/232=0.724
in 131.5kg of Fe3O4
there are 0.724*131.5=95.22kg =95220g of iron
and to have number of moles 95220/56=1700 moles of iron

Answer 3

131.5kg (1000g/1kg)*(1 molFe3O4/231.55gFe3O4)*(1 mol Fe/1 mol Fe3O4)= 567.9 mol Fe

assuming the molar ratio is 1:1. You can find that if you have the chemical equation.