Find all real zeros of the function x^5+1x^3-56x?

Answer 1

x^5 + x³ - 56x = 0
x(x^4 + x² - 56) = 0
x(x² + 8)(x² - 7) = 0
x = 0
x = ±2√2
x = ±√7

Answer 2

The real zeros are 0, +/-sqrt(7). The zeros of x^2 + 8 are not real.