x^2 - x / 2x = 3 ^x?

0 ⤊

x^2 - x / 2x = 3 ^x?

solve for x ._.
x^2 - x / 2x = 3 ^x
thanks : )

2007-11-07 16:14:34 · 2 answers · asked by Henry Chan 1 in Science & Mathematics ➔ Mathematics

2 answers

If you mean (x² - x)/2x = 3^x, there's no solution.

If you mean x² - x/(2x) = x² - 1/2 = 3^x, x = 0.278166 by way of ti-83. No nice algebraic way to solve that.

2007-11-07 16:29:57 · answer #1 · answered by Philo 7 · 0⤊ 0⤋

(x^2 -x)/2x = 3^x
(x-1)/2 = 3^x
extract ln of both sides
ln(x-1) - ln(2) = xln(3)
ln(x-1) - 0.6931 = 1.0986x
ln(x-1) = 1.0986x + 0.6931
Sorry, I forgot how to proceed from here.

2007-11-08 00:32:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋