I need to know how to work this out. I have the answer just need to know how to get it.?

Question

How many kg of carbon dioxide are produced when 150 kg of glucose (C6H12O6) are fermented? C6H12O6->2C2H5OH + 2CO2.

Answer 1

C6H12O6 --> 2C2H5OH + 2CO2
1 mole of glucose will produce 2 moles of CO2
1 mole of glucose has a mass of 180.2 g
1 mole of CO2 has a mass of 44.01 g
150,000 g glucose / 180.2 g per mole = 832.4 moles
2x832.4 = 1664.8 moles of CO2
1664.8 moles x 44.01 g per mole = 73.3 kg CO2

Answer 2

use the 'molar concept'.

So you've got your balanced reaction and it tells you that 1 molecule of glucose gives you 2 molecules of CO2.

Now find the molecular weight of glucose (180 g) and the molecular weight of carbon dioxide (44 g).

So 180g of glucose gives you 44 g of carbon dioxide.
i.e. 1 g of glucose gives you 44/180 g of co2
150 kg of glucose gives you (answer) g of CO2

Answer 3

Take the ratio of the molecular weights of the products.
(The CO2 to the alcohol) and multiply by 150Kg.