Logarithm solution...?

Question

log base 4 of (4x) - log base 4 of (x/4) = 3



Sorry, it's kind of hard to type without html.

Thank you

No you are using log base 10 (simply "log" on a calulator) not the same as log base 4

Answer 1

Logs are referring to log (base 4)

log(4x) - log(x/4) = 3
log(4x / (x/4)) = 3
log(4x * 4/x) = 3
log(16) = 3
2 = 3

No valid solution


log(16) base 4 is 2
log(16) base 4 is log(16)/log(4)

log(16) = log(4*4) = log(4) + log(4) = 2log(4)
2log(4)/log(4)
= 2/1
= 2

Answer 2

Use the rule that Log(A) - Log(B) -Log(A/B):

(in this problem all logs are base 4)
So: Log(4x / (x/4) ) = Log (16) = x

4^Log(16) = 4^x
16 = 4^x
So X=2

Not 3 as you show in your question.

Answer 3

Recall that log_4 a - log_4 b = log_4 a/b.
So we can write the left side of your equation as
log_4 (4x)/(x/4) = log_4 16
But log_4 16 = 2, since 4² = 16.
So there is no solution to your problem.

Answer 4

∅

No solution

I keep getting 2 = 3... and I hope you realize by now that -that- simply isnt true.

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Why cant you use HTML? You cant you tags... but you can still use character codes.