A 12250 N car traveling at 46.0 km/h rounds a curve of radius 2.00x10^2 m.
(a) Find the centripetal acceleration of the car.
(b) Find the force that maintains centripetal acceleration.
(c) Find the minimum coefficient of static friction between the tires and the road that will allow the car to round the curve safely
2007-11-07 14:38:56 · 2 answers · asked by Asdasd A 1 in Science & Mathematics ➔ Physics
A 12250 N car traveling at 46.0 km/h rounds a curve of radius 2.00x10^2 m.
(a) Find the centripetal acceleration of the car.
A=V^2/R
* Be sure to convert V to meters per second
V=46km/hour* 1000m/km * 1 hr/3600 sec
(b) Find the force that maintains centripetal acceleration.
First, find M
Weight=M*g
M=12250N/(9.8m/sec^2)
Second, find the Centripetal Force
F=M*A (A is from "(a)," above)
(c) Find the minimum coefficient of static friction between the tires and the road that will allow the car to round the curve safely
Min Coef friction = F/Weight
Plug in the numbers and go.
To one signicant figure A~.8m.sec, F~1,000N and μ~.08
2007-11-07 15:29:54 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 0⤊ 0⤋
by definition ac = v^2/r
here v = 46km/h but you need to convert to m/s (divide by 3.6)
r = 200m, youdo the math!
The force is given by mac, so you need the mass of the car. m = Weight/g = 12550N/9.8
since it is friction that results in ac here, umg = mac
u = ac/g = v^2/r/g
voila!
2007-11-07 15:20:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋