From the equation F = mv2/r, the tension in a 1 m length of string that whirls a 3 kg mass at 4 m/s in a horizontal circle is calculated to be 48 N. Calculate the tension for the following cases.
(a) twice the mass
(b) twice the speed
(c) twice the length of string (radial distance)
(d) twice mass, twice speed, and twice distance all at the same time
2007-11-07 14:34:58 · 1 answers · asked by Asdasd A 1 in Science & Mathematics ➔ Physics
From the equation F = mv^2/r, the tension in a 1 m length of string that whirls a 3 kg mass at 4 m/s in a horizontal circle is calculated to be 48 N. Calculate the tension for the following cases.
Remember, Tension is a force therefore,
T = mv^2/r
T = 3kg*(4m/sec)^2/1m
T= 48 N
(a) twice the mass
T= 6kg*(4m/sec)^2/1m
T= 96 N
(b) twice the speed
T = 3kg*(8m/sec)^2/1m
T = 192 N
(c) twice the length of string (radial distance)
T = 3kg*(4m/sec)^2/2m
T = 24 N
(d) twice mass, twice speed, and twice distance all at the same time
T = 6kg*(8m/sec)^2/2m
T = 196 N
2007-11-07 16:19:30 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 0⤊ 0⤋