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Okay well I'll just be honest.. I wasn't paying attention in class. And this book is confusing, as always.

So can someone explain how you get angles measurements from polygons? Like in this picture:http://i18.tinypic.com/814dx8o.gif
And what if it has say.. 17 sides?

How would you find out the measurement of the angles inside, and the angle of X?

And how do you use "180(n - 2)" to get this?
(There was some other equations like this but I forget them).

Please make it simple, thanks.

2007-11-07 14:30:08 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

to find that angle x (the exterior angle), just do 360 divided by the # of sides

to find the angles inside (interior angles), do 180 minus angle x (they're supplementary angles!)

2007-11-07 14:34:32 · answer #1 · answered by Sunian 4 · 0 1

Guess it is first class in the morning syndrone.

Anyway, the 180(n-2)= sum of inside angles of a polygon of "n" sides. For your picture, you have a regular hexagon (all sides equal). Then the sum of angles is 720, and each angle is 720/6=120.
The drawing shows "X" and one such angle are supplements or equal to 180 degrees. Now impress me and figure out what X is.

2007-11-07 14:40:33 · answer #2 · answered by cattbarf 7 · 1 0

Okay this may get confusing very fast.

1. all interior angles of the polygon will add up to 360˚.
(360/17)
2. the x angle and the interior angle will add up to 180˚ because they are supplementary ( adding to 180˚)
3. the equation you wrote is stupid don't use it. Figure out a way comfertable for you that works EVERY time.

Hope it helps!

2007-11-07 14:38:32 · answer #3 · answered by Call me K 2 · 0 1

Go to http://regentsprep.org/Regents/math/poly/LPoly1.htm and read it.

2007-11-07 14:34:41 · answer #4 · answered by katie72 1 · 0 1

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