Please explain.
2007-11-07 14:15:14 · 18 answers · asked by Bobby S 3 in Science & Mathematics ➔ Mathematics
ONE side of the rectangle is a line with an infinite length
2007-11-07 14:41:57 · update #1
ONE side of the rectangle is lined up with a line of infinite length
2007-11-07 14:43:06 · update #2
Length means perimeter
2007-11-07 14:43:45 · update #3
Well if you mean lenth, then the area can be as big as 500*width
but you probably mean perimeter
so, it would be 15625 m^2
2007-11-07 14:18:59 · answer #1 · answered by oO_SPIFFY_TOOL_Oo 1 · 0⤊ 0⤋
500 x 500 if you consider a square a rectangle. If the length is 500m, the other side can't be longer than 500m.
So 500 x 500 is the largest area possible.
2007-11-07 14:19:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The area is infinite
* The area of a rectangle can be found by multiplying the base times the height.
* If a rectangle has a base of length 6 inches and a height of 4 inches, its area is 6*4=24 square inches
2007-11-07 14:17:25 · answer #3 · answered by Harry W 3 · 0⤊ 1⤋
the place it includes rectangles, the sq. consistently supplies the optimum section (75ft x 75ft). you may teach this employing calculus (the optimum element while plotting section against width is 5626ft section for 75ft width, so length must additionally be 75ft via subtraction and branch of perimeter) like so: Perimeter P = 2 * length L + 2 * Width W P = 2L + 2W 2L = P - 2W L = P/2 - W L = a hundred and fifty - W hence section A = length L * Width W A = LW A = W (a hundred and fifty - W) A = -W^2 + 150W the optimum element in this curve may be discovered via taking the 1st spinoff: dA/dW = -2W + a hundred and fifty it particularly is 0 while a hundred and fifty = 2W 75 = W all of us understand this could be a optimum element with the aid of fact the 2d spinoff is -2 for the time of, so there are no minimum factors.
2016-12-08 15:20:17 · answer #4 · answered by ? 4 · 0⤊ 0⤋
125^2. Without offering a proof, the maximum-sized rectangle is a square. Then each side is 500/4, and the base x height is the area.
2007-11-07 14:19:00 · answer #5 · answered by cattbarf 7 · 0⤊ 0⤋
Impossible unless you specify that the length will always be the longest side whether it's the horizontal or vertical side.
If so, your max area will be2495 sq m.
Thats 500 x 499 (max width or it would become a square)
2007-11-07 14:22:02 · answer #6 · answered by michaelsmaniacal 5 · 0⤊ 0⤋
To stay a rectangle the other sides can't be 500. They have to be less, so the max is 499. Multiply 500 by 499.
2007-11-07 14:18:00 · answer #7 · answered by ugh192 4 · 0⤊ 1⤋
Unlimited. Nothing has been said about any constraint on the width. However, if we suppose that "length" refers to the longer dimension, then the width can be up to 500 meters, so the area would be 250,000 square meters.
2007-11-07 14:19:08 · answer #8 · answered by Anonymous · 0⤊ 0⤋
the width could be infinite in measurement, so it cannot be determined. If you state that the width cannot exceed the length, then it would be a square of 500m x 500m = 250,000 sq./m
2007-11-07 14:21:13 · answer #9 · answered by StayThirstyMyFriends 6 · 0⤊ 0⤋
infinity...due to the dimension of its width, remember a square is a rectangle, and once your rectangle gets to 500x500, the width is still the width, until you change the number definition
LxW=A so as long as you keep L= to 500, W can be anything.
2007-11-07 14:21:02 · answer #10 · answered by hangarrat 2 · 0⤊ 0⤋