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6x^2-31x+28=0


answers given are x=4 and 7/6

2007-11-07 13:45:56 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

hmmmmmmmmmm
factors for 6 = 1,6 and 2,3
factors for 28 4,7 and 1,28
since the third number is positive - must assume that
both numbers are negative to make 2nd number negative

if both second and third were negative - then
the factors subtracted would make the higher number negative

(x-4) (6x - 7) = 0

2007-11-07 13:52:11 · answer #1 · answered by tom4bucs 7 · 0 0

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