find the sum of the reciprocals of the first positive powersof three. express your answer in as acommonfracton

Question

find the sum of the reciprocals of the first positive powers of three. express your answer in as a common fraction

please show how u got the answer.

THIS ISN'T A HW QUESTION

PLEASE PLEASE SHOW UR WORK

please asap

what this question means by first five powers of three is 1^3, 2^3, 3^3, 4^3, 5^3

it doesnt mean 3^1, 3^2, 3^3, 3^4, 3^5

THIS IS WRONG WRONG WRONG

Answer 1

ok. idont get it either

Answer 2

The first 5 positive powers of 3 are:

3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243

The reciprocals would be 1 divided by each of these numbers, namely:
1/3 + 1/9 + 1/27 + 1/81 + 1/243

Now to add these you need a common denominator, which will be 243. Converting to the same denominator you have:
81/243 + 27/243 + 9/243 + 3/243 + 1/243

Adding together you have:
(81 + 27 + 9 + 3 + 1) / 243
=121/243

This can't be reduced further, so you are done:
Answer = 121/243