PLEASE HELP! Masses connected to pulley, linear speed!?!?

Question

Consider two mass, 3.2kg and 7.1kg, connected by a string passing over a pulley having a moment of inertia 11gm^2 about its axis of rotation. The string doesn't slip on the pulley, and the system is released from rest. The radius of the pulley is 0.33m.

Find the linear speed of the masses after the 7.1kg mass descends through a distance 33cm. Assume mechanical energy is conserved during the motion.

PLEASE PLEASE HELP!!!!

Answer 1

The energy equation for this is
(7.1-3.2)*0.33=
.5*(7.1+3.2)*v^2+.5*0.011*v^2/0.33^2

2*(7.1-3.2)*0.33/*((7.1+3.2)+.5*0.011/0.33^2)=
v^2

v=0.50 m/s

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