fin f such that given conditions are satisfied. f'(x)= x^2 +7, f(0)=25?

Answer 1

aren't u suppose to find X cuz isn't F the function sign?

Answer 2

First, integrate the first derivative expression....

f(x) = integral of f'(x) = (x^3/3) + 7x + C***

***Note: C is a constant of integration, which can be found if a condition is given.....in this case, the "condition" is f(0) = 25

f(0) = 1/3*(0)^3 + 7*(0) + C = 25 ----------> C = 25

The function which satisfies all of the conditions is:

f(x) = x^3/3 + 7x + 25

Answer 3

integrate f'(x)
f(x) = (x^3)/3 + 7x + c (c is a constant)

at x=0, c = 25